Suppose that f = 0101 0000 0000 0000 0000 000, e = 1000 1111, and s=0.

The significand is 1.0101 0000 0000 0000 0000 000 because of the implied "1." in front of the 23-bit number. This translates to 1.0 + 1/4 + 1/16, or 1.3125.

The decimal value of the exponent field is 143. The "real" exponent, then, is 143 - 127 = 16 (or 1000 1111 - 0111 1111 in binary, which is 0001 0000. You are welcome either to compute in binary or to convert everything into decimal and use a calculator.)

The sign is +.

So the binary number is + 1.0101 0000 0000 0000 0000 000 times 2^(0001 0000).

The decimal number is 1.3125 x 2^16 or 1.3125 x 65536 or 86016, if I've plugged the numbers in right.

On a quiz, you need not do out the last gory details of the arithmetic; for instance, any of those three forms of the decimal answer would be equally acceptable.